作业帮(1-tan^2π/12)/(tanπ/12)化简
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(1-tan^2π/12)/(tanπ/12)化简
(1-tan^2π/12)/(tanπ/12)化简
(1-tan^2π/12)/(tanπ/12)化简
(1-tan^2π/12)/(tanπ/12)
=2*(1-tan^2π/12)/(2tanπ/12)
=2/(tanπ/6)
=2√3/3
由tan（2x）＝2tanx／1－tan＾2x得
(tanπ/12)/(1-tan^2π/12）＝1／2tan（π／6）＝六分之根号三
所以(1-tan^2π/12)/(tanπ/12)＝二倍的根号三
tan(π/12)-(1/tan(π/12))
(1-tan^2π/12)/(tanπ/12)化简
计算tanπ/12 / (1-tan^2π/12)=
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计算 tanπ/12+1/tanπ/12
tan(π/12)+1/tan(π/12)=啥?
tanπ/12-1/tanπ/12=
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