作业帮计算tanπ/12 / (1-tan^2π/12)=
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计算tanπ/12 / (1-tan^2π/12)=
计算tanπ/12 / (1-tan^2π/12)=
计算tanπ/12 / (1-tan^2π/12)=
tanπ/12 / (1-tan^2π/12)
=1/2*(2tanπ/12) / (1-tan^2π/12)
=1/2*tan(π/12+π/12)
=1/2*tanπ/6
=1/2*√3/3
=√3/6
tanx/(1-tan^2x)
=(sinx/cosx)/(1-sin^2x/cos^2x)
=(sinx/cosx)/((cos^2x-sin^2x)/cos^2x)
=sinxcosx/(1-sin^2x-sin^2x)
=2sinxcosx/2cos2x
=sin2x/2cos2x
=(1/2)tan2x
将x=π/12代入
原式=(1/2)tan2*π/12
=(1/2)tanπ/6
=√3/6
计算tanπ/12 / (1-tan^2π/12)=
计算 tanπ/12+1/tanπ/12
(1-tan^2π/12)/(tanπ/12)化简
tan(π/12)-(1/tan(π/12))
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tan(π/12)+1/tan(π/12)=啥?
tanπ/12-1/tanπ/12=
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tan(π/2+1)=?tan(1-π/2)=?
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