已知x=√20-4/2,求x2+1/x2

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已知x=√20-4/2,求x2+1/x2

已知x=√20-4/2,求x2+1/x2
已知x=√20-4/2,求x2+1/x2

已知x=√20-4/2,求x2+1/x2
x=√20-4/2=2√5-4/2=√5-2
x²+1/x²
=(x+1/x)²-2
=[√5-2+1/(√5-2)]²-2
=(√5-2+√5+2)²-2
=(2√5)²-2
=20-2
=18
如追加其它问题,

x=(根号20-4)/2=(2√5-4)/2=√5-2
1/x=1/(√5-2)=√5+2

x^2+1/x^2
=x^2+1/x^2 -2+2
=(x-1/x)^2+2
=[√5-2-(√5+2)]^2+2
=16+2
=18你也很好好是没用的我再提个问 帮我回答你点求助我,我就知道哪题了已知a+b=-11.a×b=6.求...

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x=(根号20-4)/2=(2√5-4)/2=√5-2
1/x=1/(√5-2)=√5+2

x^2+1/x^2
=x^2+1/x^2 -2+2
=(x-1/x)^2+2
=[√5-2-(√5+2)]^2+2
=16+2
=18

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