热力学第二定律习题A system absorbs 473 J of heat reversibly from a hot reservoir at 529 K and gives off 182.1 J of heat to a cold reservoir at 213 K.During this process,124.6 J of work is done by the system从热源中吸收473J热量可逆,

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/12 04:38:29
热力学第二定律习题A system absorbs 473 J of heat reversibly from a hot reservoir at 529 K and gives off 182.1 J of heat to a cold reservoir at 213 K.During this process,124.6 J of work is done by the system从热源中吸收473J热量可逆,

热力学第二定律习题A system absorbs 473 J of heat reversibly from a hot reservoir at 529 K and gives off 182.1 J of heat to a cold reservoir at 213 K.During this process,124.6 J of work is done by the system从热源中吸收473J热量可逆,
热力学第二定律习题
A system absorbs 473 J of heat reversibly from a hot reservoir at 529 K and gives off 182.1 J of heat to a cold reservoir at 213 K.During this process,124.6 J of work is done by the system
从热源中吸收473J热量可逆,温度为529K,释放了182.1J的热量给冷物体,温度为213K,在这个过程中,做了124.6J的功.
求这个过程中1.内能变化J 2.熵的变化J/K 3.宇宙熵的变化

热力学第二定律习题A system absorbs 473 J of heat reversibly from a hot reservoir at 529 K and gives off 182.1 J of heat to a cold reservoir at 213 K.During this process,124.6 J of work is done by the system从热源中吸收473J热量可逆,
内能的变化是：
473-182.1-124.6
这里,系统熵的变化：529K的热源放热Q1=473,熵变是-473/529,213K的热源的熵变是正的,182.1/213,两者的和就是总熵变.
然后宇宙熵变是0.因为这是可逆过程.

热力学第二定律习题A system absorbs 473 J of heat reversibly from a hot reservoir at 529 K and gives off 182.1 J of heat to a cold reservoir at 213 K.During this process,124.6 J of work is done by the system从热源中吸收473J热量可逆, build a strong immune system immune system 、、、 热力学第二定律理解 热力学第二定律是什么意思 何谓热力学第二定律? 何谓热力学第二定律? 简述热力学第二定律. 简述热力学第二定律. a new system of elections 和 a radio broadcaating system System SYSTEM. system system. system system system-on-a-chip是什么意思 public class hh {public static void main (String args[]){A aa = new A();aa.num =5;hh t = new hh();System.out.println(11 aa=+aa + num=+aa.num);t.test(aa);System.out.println(22 aa=+aa + num=+aa.num);} void test(A a){A ab = new A();a = ab;System 均值不等式习题a>0,b>0,ab=a+b+3,求a+b最小值.