(x-y-2)2+x+y+1的值

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(x-y-2)2+x+y+1的值

(x-y-2)2+x+y+1的值
(x-y-2)2+x+y+1的值

(x-y-2)2+x+y+1的值
(x-y-2)^2+x+y+1的绝对值=0
所以
x-y-2=0
x+y+1=0
所以x-y=2
x+y=-1
所以
(x-y)^2+3(x+y)^3-2(x-y)^2-(x+y)^3
=-(x-y)^2+2(x+y)^3
=-4+(-2)
=-6
这样可以么?

3x-y-7

3x-y-3

3X-y-7

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