平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为B'..平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为

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平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为B'..平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为

平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为B'..平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为
平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为B'..
平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为B',求DB’的长度.
如图

平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为B'..平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为
将三角形ABC翻折后,得三角形AB'C,连接B'E,得BE=B'E=1,∠BEB'=90°∠B'BD=45°=∠BB'E
因为∠B'ED=90° EB'=ED 所以∠EB'D=∠EDB'=45°所以B'D=√(1²+1²)=√2

根号2,连BB’得到DBB’是等腰直角三角形
有两个人给出同一答案,3L说题意不清,什么情况???

这题题意表达不清

Wholesale Dropship Companies - The way to Spot a Scam
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Drop Ship Wholesalers
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First of all, let's discuss the way to identify an actual wholesaler. ...

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Wholesale Dropship Companies - The way to Spot a Scam
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Drop Ship Wholesalers
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First of all, let's discuss the way to identify an actual wholesaler. This can be a rather easy step, plus the previous installment,Nike Air Max 91, we touched this topic. As I mentioned,Nike Air Max 1, no real wholesale supplier can or will sell to most people. For this reason, they have to have proof that you are a real business owner before they are able to do business with you.
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The next topic I want to discuss today is how you can protect yourself from fraudulent sellers. Unfortunately, there are numerous of scammers out there desperate to take advantage of retailers. Because of this,Nike Air Max Skyline, I recommend which you purchase everything through a couple of options:1 - Pick it up and pay for it face-to-face.2 - Make use of a Bank card so that you will may file a chargeback if you're defrauded from the seller.3 - Don't use anything but PayPal In the event you fund the payment with a charge card. (Explained Below).These three payment methods will almost guarantee your protection from wholesale scams,sale cheap Nike air max 24/7, and that i only advise paying using permanently once you learn a supplier as honest, otherwise you highly trust the recommendations of your colleague. When first employing a wholesaler, Avoid the use of a money order or cashiers check, and run one other way in case you are approached with a seller wanting one to pay by Western Union. This is the payment approach to option for many overseas scams.

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连接B'E 证明ABE全等AB'E (AB=AB’ ∠BAE=∠B'AE AE=AE) 所以∠B'EA=∠BEA=45° BE=B'E=1 ∠B'EB=∠B'EA+∠BEA=90° 在RT△B'ED中 根据勾股定理得:剩下不用说了 知道B'E=1 ED=1 B'D就=根号5

连接B'E 证明ABE全等AB'E (AB=AB’ ∠BAE=∠B'AE AE=AE) 所以∠B'EA=∠BEA=45° BE=B'E=1 ∠B'EB=∠B'EA+∠BEA=90° 在RT△B'ED中...

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连接B'E 证明ABE全等AB'E (AB=AB’ ∠BAE=∠B'AE AE=AE) 所以∠B'EA=∠BEA=45° BE=B'E=1 ∠B'EB=∠B'EA+∠BEA=90° 在RT△B'ED中 根据勾股定理得:剩下不用说了 知道B'E=1 ED=1 B'D就=根号2
刚刚说错 不好意思啊

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已知平行四边形ABCD中,AC,BD交于O,E是平行四边形外一点,且∠AEC=∠BED=90°,求证平行四边形ABCD是矩形 平行四边形ABCD对角线AC、BD相交于O,EO⊥BD交AB于E,AE=OE=1/2BE,求证:平行四边形ABCD是矩形 一道初二的平行四边形的数学题!如图,平行四边形ABCD中,AC交BD于O,AE⊥BD于E,∠EAD=60°,AE=2cm,AC+BD=14cm,求三角形BOC的周长 已知四边形ABCD为矩形,AC,BD交于O点,DE=BD,且DE与BC延长线交于E,求证:四边形ABCD为平行四边形 平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为B'..平行四边形ABCD,AC,BD交于E,∠AEB=45°,BD=2 将三角形ABC沿AC所在直线翻折到同一平面内,点B的落点为 在平行四边形ABCD中,AC,BD交于点O,AE垂直于BC于点E,EO交AD与点F,求证,平行四边形AECF为矩形 初二平行四边形的性质问题1、在平行四边形ABCD中,AB≠AD,AC,BD相交于O,OE⊥BD交AD于E,求证:OB平分∠CBE.2、在平行四边形ABCD中,∠BCD的平分线CE交AD于E,∠ABC的平分线BG交CE于F,交AD于G.①求证 BG⊥CE ② 已知平行四边形ABCD,AC,BD交于点O,E是平行四边形ABCD外一点,且∠AEC=∠BED=90°求证平行四边形ABCD是矩形 如图,已知平行四边形ABCD,AC与BD交于点O,E是平行四边形ABCD外的一点,且∠AEC=∠BED=90°.求证:平行四边形ABCD是矩形. 如图,在平行四边形ABCD中,AC,BD相交于点O,AC=6,BD=8,∠AOD=65°,点E在BO上,AF平行于CE交BD于点如图,在平行四边形ABCD中,AC,BD相交于点O,AC=6,BD=8,∠AOD=65°,点E在BO上,AF平行于CE交BD于点 如图,平行四边形ABCD的周长为36,对角线AC,BD交于点O,OE⊥BD,交DC于点E.求ΔCBE的周长 如图,平行四边形ABCD中,对角线AC与BD交于点O,EO⊥BD,垂足为O,OE交DC的延长线于E 平行四边形ABCD对角线AC,BD交于点O,AE=EB(E为AB中点).求证OE//BC 平行四边形ABCD周长为16,AC,BD交于O,OE垂直AC交AD于E,求三角形DEC的周长 如图,平行四边形ABCD的对角线AC,BD交于O,EF过点O交AD于E,交BC于F如图,平行四边形abcd的对角线ac,bd交于o,ef过点o交ad于e,交bc于f,g是oa的中点,四边形egfh是平行四边形,请说明理由 平行四边形ABCD对角线AC、BD交于O,AE⊥BC于E,EO延长线交AD于F 连结CF求证四边形AECF为矩形 平行四边形ABCD中,AC与BD交于点O,AE⊥BD垂足为E,∠EAD=60°,AE=2cm,AC+BD=14cm,则△BOC的周长是________. 如图,平行四边形ABCD的对角线AC BD交于O,EF过点O交AD与E,交BC于F,G如图,平行四边形ABCD的对角线AC BD交于O,EF过点O交AD与E,交BC于F,G是OA中点,H是OC中点,求证:四边形EGFH是平行四边形.