作业帮MATLAB 向量相乘的问题已知 t=0:1:20;A=[1,0,0;0,1,0;0,0,1];B=[-sin(t),cos(t),sin(t);-t,t,tan(t);sin(t),cos(t),cos(t)];C=[1,0,1;0,1,0;0,0,1];如何求A*B*C
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/30 04:26:04
![MATLAB 向量相乘的问题已知 t=0:1:20;A=[1,0,0;0,1,0;0,0,1];B=[-sin(t),cos(t),sin(t);-t,t,tan(t);sin(t),cos(t),cos(t)];C=[1,0,1;0,1,0;0,0,1];如何求A*B*C](/uploads/image/z/4956650-26-0.jpg?t=MATLAB+%E5%90%91%E9%87%8F%E7%9B%B8%E4%B9%98%E7%9A%84%E9%97%AE%E9%A2%98%E5%B7%B2%E7%9F%A5+t%3D0%3A1%3A20%3BA%3D%5B1%2C0%2C0%3B0%2C1%2C0%3B0%2C0%2C1%5D%3BB%3D%5B-sin%28t%29%2Ccos%28t%29%2Csin%28t%29%3B-t%2Ct%2Ctan%28t%29%3Bsin%28t%29%2Ccos%28t%29%2Ccos%28t%29%5D%3BC%3D%5B1%2C0%2C1%3B0%2C1%2C0%3B0%2C0%2C1%5D%3B%E5%A6%82%E4%BD%95%E6%B1%82A%2AB%2AC)
MATLAB 向量相乘的问题已知 t=0:1:20;A=[1,0,0;0,1,0;0,0,1];B=[-sin(t),cos(t),sin(t);-t,t,tan(t);sin(t),cos(t),cos(t)];C=[1,0,1;0,1,0;0,0,1];如何求A*B*C
MATLAB 向量相乘的问题
已知 t=0:1:20;
A=[1,0,0;0,1,0;0,0,1];
B=[-sin(t),cos(t),sin(t);-t,t,tan(t);sin(t),cos(t),cos(t)];
C=[1,0,1;0,1,0;0,0,1];
如何求A*B*C
MATLAB 向量相乘的问题已知 t=0:1:20;A=[1,0,0;0,1,0;0,0,1];B=[-sin(t),cos(t),sin(t);-t,t,tan(t);sin(t),cos(t),cos(t)];C=[1,0,1;0,1,0;0,0,1];如何求A*B*C
t为向量的话,B的维数为3*63不满足矩阵的乘法
故t为标量
直接计算可得
A 是单位矩阵,A*B=B
A*B*C = B*C = [-sin(t),cos(t),0;-t+tan(t),t,tan(t);sin(t)+cos(t),cos(t),cos(t)];
用Matlab的话就直接相乘就好
for t = 0:1:20
A=[1,0,0;0,1,0;0,0,1];
B=[-sin(t),cos(t),sin(t);-t,t,tan(t);sin(t),cos(t),cos(t)];
C=[1,0,1;0,1,0;0,0,1];
answer(t+1,:,:) = A*B*C;
end
求助！MATLAB 向量相乘的问题
已知 t=0:1:20;
A=[1,0,0;0,1,0;0,0,1];
B=[-sin(t),cos(t),sin(t);-t,t,tan(t);sin(t),cos(t),cos(t)];
C=[1,0,1;0,1,0;0,0,1];
如何求A*B*C
回答:楼上办法针对这个问题是可行的
你的...
全部展开
求助！MATLAB 向量相乘的问题
已知 t=0:1:20;
A=[1,0,0;0,1,0;0,0,1];
B=[-sin(t),cos(t),sin(t);-t,t,tan(t);sin(t),cos(t),cos(t)];
C=[1,0,1;0,1,0;0,0,1];
如何求A*B*C
回答:楼上办法针对这个问题是可行的
你的问题属于不同维数相乘，没有好办法解决，建议用循环一个一个输出
毕竟这取决于你实际处理的问题（ 如果你坚持计算ABC 元胞数组可以解决这个问题）
比如
for t=0:1:20
A=[1,0,0;0,1,0;0,0,1];
B=[-sin(t),cos(t),sin(t);-t,t,tan(t);sin(t),cos(t),cos(t)];
C=[1,0,1;0,1,0;0,0,1];
A*B*C
end
收起