英语翻译Dyadic observations are not independent since E[U(ij) ; U(ik)] =0 for all i and E[uij ; ukj ] =0 for all j.We also have E[uij ; ujk] = 0 and E[uij ; uki]!= 0.Provided that regressors are exogenous,applying OLSto (I.2) and (I.3) yields con

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英语翻译Dyadic observations are not independent since E[U(ij) ; U(ik)] =0 for all i and E[uij ; ukj ] =0 for all j.We also have E[uij ; ujk] = 0 and E[uij ; uki]!= 0.Provided that regressors are exogenous,applying OLSto (I.2) and (I.3) yields con

英语翻译Dyadic observations are not independent since E[U(ij) ; U(ik)] =0 for all i and E[uij ; ukj ] =0 for all j.We also have E[uij ; ujk] = 0 and E[uij ; uki]!= 0.Provided that regressors are exogenous,applying OLSto (I.2) and (I.3) yields con
英语翻译
Dyadic observations are not independent since E[U(ij) ; U(ik)] =0 for all i and E[uij ; ukj ] =0 for all j.
We also have E[uij ; ujk] = 0 and E[uij ; uki]!= 0.Provided that regressors are exogenous,applying OLS
to (I.2) and (I.3) yields consistent coefficient estimates but standard errors are inconsistent.To obtain
consistent standard errors,we extend the method that Timothy J.Conley developed to deal with spatial
correlation of errors:

英语翻译Dyadic observations are not independent since E[U(ij) ; U(ik)] =0 for all i and E[uij ; ukj ] =0 for all j.We also have E[uij ; ujk] = 0 and E[uij ; uki]!= 0.Provided that regressors are exogenous,applying OLSto (I.2) and (I.3) yields con
译文：
二元观察不是独立的,因为 E[U(ij) ; U(ik)] !=0 对所有 i 且 E[uij ; ukj ] !=0 对所有 j.
我们还有 E[uij ; ujk] != 0 且 E[uij ; uki]!= 0.假定回归量都是外生的,把 OLS
运用于(I.2) 和(I.3) 则导致一致的系数估计,但标准误差仍是不一致的.为了获得一致的标准误差,我们把Timothy J.Conley发展的方法扩展成能处置误差的空间关联:

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矢意见并非独立自e [ U （下标ij ） ;铀（ IK ）的] ！ = 0 ，我和E [ uij ; ukj ] ！ = 0对所有j.我们也有e [ uij ; ujk ] ！ = 0和E [ uij ; uki ] ！ = 0 。只要regressors是外源，运用生命线行动，以（ 1.2 ）和（ 1.3 ）相一致的收益系数估计，但标准差是不一致的。获得一致的标准错误，我们扩展的方法，蒂莫西j...

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矢意见并非独立自e [ U （下标ij ） ;铀（ IK ）的] ！ = 0 ，我和E [ uij ; ukj ] ！ = 0对所有j.我们也有e [ uij ; ujk ] ！ = 0和E [ uij ; uki ] ！ = 0 。只要regressors是外源，运用生命线行动，以（ 1.2 ）和（ 1.3 ）相一致的收益系数估计，但标准差是不一致的。获得一致的标准错误，我们扩展的方法，蒂莫西j. conley开发出对付的空间相关性的错误

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大意是： 二的观察从E [U (ij)不是独立的; U (ik)] ! 所有的=0 i和E [uij; ukj]! 所有j. 的=0We也有E [uij; ujk]! = 0和E [uij; uki]! = 0。 在regressors是外生的条件下，应用OLS
to (I.2)和(I.3)出产量一致的系数估计，但是标准误差是不一致的。 获得
consistent标准误差，我们...

全部展开

大意是： 二的观察从E [U (ij)不是独立的; U (ik)] ! 所有的=0 i和E [uij; ukj]! 所有j. 的=0We也有E [uij; ujk]! = 0和E [uij; uki]! = 0。 在regressors是外生的条件下，应用OLS
to (I.2)和(I.3)出产量一致的系数估计，但是标准误差是不一致的。 获得
consistent标准误差，我们扩大Timothy J. Conley开发应付空间的方法错误的correlation ：
应该是这样了

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dyadic regulation 是什么意思 英语翻译1、These findings are distinct from mainstream buyer–supplier relationship researches in that our dyadic analysis provides a richer understanding of effective governance structure by recognizing the role of strategic interdependence as 英语翻译Dyadic observations are not independent since E[U(ij) ; U(ik)] =0 for all i and E[uij ; ukj ] =0 for all j.We also have E[uij ; ujk] = 0 and E[uij ; uki]!= 0.Provided that regressors are exogenous,applying OLSto (I.2) and (I.3) yields con 英语翻译A dyadic relationship is undirectional if Y(ji) = Y(ij) for all i; j.In this case,symmetry requires thatregressors satisfy DX(ij) = DX(ji).One easy way of satisfying this requirement is to specify the regressionas:where Z(i) and Z(j) are To avoid the various foolish opinions to which mankind are prone,no superhuman genius is required．A few simple rules will keep you,not from all error,but from silly error． If the matter is one that can be settled by observation,make the observati 英语翻译 英语翻译 英语翻译 英语翻译 英语翻译 英语翻译 英语翻译 英语翻译 英语翻译 英语翻译 英语翻译 英语翻译 英语翻译