用matlab求二重积分[1+cos(6*pi*x+8*pi*y)]*exp(-j*2*pi*(3*x+4*y)),试了好多次貌似都有错syms x y>> double (int(int(1+cos(6*pi*x+8*pi*y)*exp(-j*2*pi*(3*x+4*y)),-inf,inf),-inf,inf))Warning:Could not attach the property of being closeto the

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/01 19:43:03
用matlab求二重积分[1+cos(6*pi*x+8*pi*y)]*exp(-j*2*pi*(3*x+4*y)),试了好多次貌似都有错syms x y>> double (int(int(1+cos(6*pi*x+8*pi*y)*exp(-j*2*pi*(3*x+4*y)),-inf,inf),-inf,inf))Warning:Could not attach the property of being closeto the

用matlab求二重积分[1+cos(6*pi*x+8*pi*y)]*exp(-j*2*pi*(3*x+4*y)),试了好多次貌似都有错syms x y>> double (int(int(1+cos(6*pi*x+8*pi*y)*exp(-j*2*pi*(3*x+4*y)),-inf,inf),-inf,inf))Warning:Could not attach the property of being closeto the
用matlab求二重积分[1+cos(6*pi*x+8*pi*y)]*exp(-j*2*pi*(3*x+4*y)),试了好多次貌似都有错
syms x y
>> double (int(int(1+cos(6*pi*x+8*pi*y)*exp(-j*2*pi*(3*x+4*y)),-inf,inf),-inf,inf))
Warning:Could not attach the property of being close
to the limit point to limit variable [limit]
Warning:Explicit integral could not be found.
Error using ==> mupadmex
Error in MuPAD command:DOUBLE cannot convert the
input expression into a double array.

用matlab求二重积分[1+cos(6*pi*x+8*pi*y)]*exp(-j*2*pi*(3*x+4*y)),试了好多次貌似都有错syms x y>> double (int(int(1+cos(6*pi*x+8*pi*y)*exp(-j*2*pi*(3*x+4*y)),-inf,inf),-inf,inf))Warning:Could not attach the property of being closeto the
function f=fun(x,y)
f=1+cos(6*pi.*x+8*pi.*y).*exp(-j*2*pi*(3.*x+4.*y));
end
>> f=@(x,y) fun(x,y);
Q=dblquad(f,0,2*pi,0,2*pi)
Q =
59.2170 - 0.0001i
>> f=@(x,y)fun(x,y);
Q=dblquad(f,-inf,inf,-inf,inf)
Q =
NaN + NaNi

MATLAB如何求二重积分 怎样用matlab求二重积分 matlab求二重积分 如何用matlab求二重积分 用matlab求二重积分[1+cos(6*pi*x+8*pi*y)]*exp(-j*2*pi*(3*x+4*y)),试了好多次貌似都有错syms x y>> double (int(int(1+cos(6*pi*x+8*pi*y)*exp(-j*2*pi*(3*x+4*y)),-inf,inf),-inf,inf))Warning:Could not attach the property of being closeto the 怎么用Matlab计算这个二重积分?求程序代码作业不会啊 急 悬赏200分求高手帮忙用matlab求出此二重积分的结果, 用matlab求dx/(1+cos(x))的不定积分怎么求 怎么用MATLAB求函数x*(1+cos(x))*cos(x)^2,x在[0,pi]上, 二重积分啊!求二重积分 10^6+10^4*cos(2*pi)*10^3t这个函数用matlab求积分. 求二重积分, 求二重积分～ 求二重积分, 求二重积分! 怎么用matlab求cos（2x）+sin（x)=1的解捏~求代码 Matlab积分Mindlin解我在用Matlab二重积分Mindlin解的时候,出现无法计算的问题.syms a c;for i=1:nfor j=1:n z=d1*i-d1/2;R1=sqrt((d*cos(a))^2+(z-c)^2);R2=sqrt((d*cos(a))^2+(z+c)^2); A=(1+u)/(8*pi*(1-u))*((3-4*u)/R1+(z-c)^2/R1^3+(8*u^2 用直角坐标系求二重积分（x-y）^2的二重积分D:X[1,2] y[-1,0]