log5[log2(log9/log3)]=?

log5[log2(log9/log3)]=? 化简:log2 2+log5 1-3^(2log9 5)+(3log3 5)^2+3^log3 2 log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12= log2[log3[log5 125]]=?log2[log3[log5 125]]=? (log2)和(log3)变成(log5) (log2^3 +log3^5) x ( log3^5 +log9^5 ) x lg 2 ,本人对数特别差,最好带解说,(log2^3 +log5^3) x ( log3^5 +log9^5 ) x lg 2 化简log2[log3(log5 125)]……1.化简log2[log3(log5 125)]2.5log2(log9 81)3.log9 4 +log3 8 /log1/3 164.求值(lg2)^2+两个2*lg5+lg503.log9 4 +log3 8除以log三分之一 16 4.求值(lg2)平方+lg2乘以lg5+lg50 利用换底公式求值：1.log2 25 ×log3 4 ×log5 9 2.（log4 3+log8 3）（log3 2+log9 2） 计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15 几道对数数学题利用对数换底公式化简下列各题1.log2 3 · log3 4 · log4 5 · log5 22.(log4 3 + log8 3)(log3 2+log9 2)3.2log5 25 - 3log2 64还有我问一个对数方法,就是对数相乘怎么算比如：2log5 25· log5 2只有今 (log3^4+log5^2)(log2^9+log2^根号3) 1.loga c*logc a2.log2 3*log3 4*log4 5*log5 23.(log4 3+log8 3)(log3 2+log9 2)还有 5的多少次方等于1.这么计算? 1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 2)一定要详细的不能在详细.第二道题中的·那个8打错了应去掉 高中数学题log2^25 * log3^4 * log5^9 log2^25*log3^2倍根号2*log5^9= log2^5*log3^2倍根号2*log5^9= log3 25×log2 27×log5 2^-3=_____ log2(a)=log3(b)=log5(c)