lim(sin(x^2*cos(1/x)))/x怎么做?

lim(sin(x^2*cos(1/x)))/x怎么做? (x^2cos^2x-sin^2x)/x^2cos^2xsin^2x （x->0）lim (x^2cos^2x-sin^2x)/x^2cos^2xsin^2x （x->0）=lim [cos^2x-(sin^2x/x^2)]/cos^2xsin^2x=lim (cos^2x-1)/sin^2x=lim -sin^2x/sin^2x=-1这样解错在哪啊?小弟感激不尽 lim(x→0) [1-cos(x^2)]/sin(x^2)tan(x^2)]=? lim(x趋近于0)(（1/sin^2 x）-(cos^2 x)/x^2)= 求 lim(x→∞)[sin(2/x)+cos(1/x)]^x的极限. X趋向于π,求lim((sin^2 X)/()1+cos^3 X) lim(x→0)(cos x)∧(1/sin 2x)＝? 【【【高数】】】这道极限怎么解?lim(sin(2/x)+cos(1/x))^x lim(x(sin)^2) 用罗必达法则解 （见图）lim [(e^x)-1/sin（5x)]x->0lim [1-cos(5x)/1-cos(7x)]x->0lim x->0 [(8^x-7^x-1)/(x^2)-1]lim [1-(6/x)]^x x->∞ lim 7cos(3x)sec(9x)x->pi/2 求lim (sin^2x+x)/(cos^2x-x) x趋向于无穷 当 x->0 ,且 x>0 时,求极限：lim ln(2*cos(x)+sin(1/x)) . 高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x , 大学微积分：lim（x→0）[(3sin x+x^2 *cos 1/X)/(1+cos x)*In(1+x)]= 求函数的极限lim((x→x/2)cosx)/(cos(x/2)-sin(x/2)) lim(sin x+cos x)^（1／X）(X趋近于零） 极限,三角函数问题lim x趋于π （sin x）^2/1+(cos x)^3等于多少? 为什么为什么lim(Δx→0)cos(x+Δx/2)*lim(Δx→0)[sin(Δx/2)/(Δx/2)] = cosx*1为什么lim(Δx→0)cos(x+Δx/2)*lim(Δx→0)[sin(Δx/2)/(Δx/2)] = cosx*1?