π到π/3 sin(x+π/3)dx 定积分

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π到π/3 sin(x+π/3)dx 定积分

π到π/3 sin(x+π/3)dx 定积分
π到π/3 sin(x+π/3)dx 定积分

π到π/3 sin(x+π/3)dx 定积分
∫sin(x+π/3) dx=∫sin(x+π/3) d(x+π/3)
=-cos(x+π/3)+C
所以原式=-cos(π/3+π/3)+cos(π+π/3)
=-cos(2π/3)-cos(π/3)
=1/2-1/2
=0

π到π/3 sin(x+π/3)dx 定积分
=-cos(x+π/3) | (π到π/3 )
=-cos(π/3+π/3)+cos(π+π/3)
=1/2-1/2
=0

∫(π→π/3) sin(x + π/3) dx
= ∫(π→π/3) sin(x + π/3) d(x + π/3)
= cos(x + π/3):[π/3→π]
= cos(π + π/3) - cos(π/3 + π/3)
= 0