解方程：｛ x/2=y/3=z/4 x+y+z=27

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解方程：｛ x/2=y/3=z/4 x+y+z=27
解方程：｛ x/2=y/3=z/4 x+y+z=27

解方程：｛ x/2=y/3=z/4 x+y+z=27
6x=4y=3z 12x+12y+12z=12*27
12x=8y
12z=16y
8y+12y+16y = 12*27
36y = 12*27
3y=27
y=9
6x=4y=4*9=36 x=6
3z=4y=4*9=36 z=12

设x/2=y/3=z/4 =A
x=2A y=3A z=4A x+y+z=9A=27 A=3 x=6 y=9 z=12

令 x/2=y/3=z/4=k
x=2k
y=3k
z=4k
x+y+z=27
2k+3k+4k=27
9k=27
k=3
x=2k=2*3=6
y=3k=3*3=9
z=4k=4*3=12

由题意可得
y=3/2x z=2x
x+y+z=27 即 x+3/2x+2x=27
得 x=6 所以
y=9 z=12

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