已知实数x,y满足x^2+y^2-6x-8y+21=0,若4x+3y+c

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已知实数x,y满足x^2+y^2-6x-8y+21=0,若4x+3y+c

已知实数x,y满足x^2+y^2-6x-8y+21=0,若4x+3y+c
已知实数x,y满足x^2+y^2-6x-8y+21=0,若4x+3y+c<0恒成立,求c的范围

已知实数x,y满足x^2+y^2-6x-8y+21=0,若4x+3y+c
因为x^2+y^2-6x-8y+21=0
所以（x-3)^2+(y-4)=4,
所以设x=2cosa+3,y=2sina+4,
-(4x+3y)=-(8sina+6cosa+24)=-[10sin(a+b)+24]≥-34
则4x+3y+c<0恒成立,得c<-(4x+3y)
故：c<-34

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