[(x-2y)(x+2y)+4(x-y)^2]÷5y

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[(x-2y)(x+2y)+4(x-y)^2]÷5y
[(x-2y)(x+2y)+4(x-y)^2]÷5y

[(x-2y)(x+2y)+4(x-y)^2]÷5y
=[(x^2-4y^2)+4(x^2-2xy+y^2)]÷5y
=(5x^2-8xy)÷5y
=(x^2/y)-(8x/5)

给个采纳，谢谢了！

=[(x^2-4y^2)+4(x^2-2xy+y^2)]÷5y
=(5x^2-8xy)÷5y
=(x^2/y)-(8x/5)=(5x^2-8xy)/5y