作业帮若f[(x-1)²]=3x²-6x+4,则f(x²)=?f(x)=?f(x+1)=?
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/02 18:31:49
![若f[(x-1)²]=3x²-6x+4,则f(x²)=?f(x)=?f(x+1)=?](/uploads/image/z/3755350-46-0.jpg?t=%E8%8B%A5f%5B%28x-1%29%26%23178%3B%5D%3D3x%26%23178%3B-6x%2B4%2C%E5%88%99f%28x%26%23178%3B%29%3D%3Ff%28x%29%3D%3Ff%28x%2B1%29%3D%3F)
若f[(x-1)²]=3x²-6x+4,则f(x²)=?f(x)=?f(x+1)=?
若f[(x-1)²]=3x²-6x+4,则f(x²)=?f(x)=?f(x+1)=?
若f[(x-1)²]=3x²-6x+4,则f(x²)=?f(x)=?f(x+1)=?
f[(x-1)²]=3x²-6x+4=3（x²-2x+1)+1
∴f(x)=3x+1
f(x²)==3x²+1
f(x+1)==3(x+1)+1=3x+4