约分:(1)x^2+6x+9/x^2-9(2)m^-3m+2/m^-m通分:(1)x/6ab^2,y/9a^2bc(2)1/m-n,2/n^2-m^2,3n/2(m+n)求解答,

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约分:(1)x^2+6x+9/x^2-9(2)m^-3m+2/m^-m通分:(1)x/6ab^2,y/9a^2bc(2)1/m-n,2/n^2-m^2,3n/2(m+n)求解答,

约分:(1)x^2+6x+9/x^2-9(2)m^-3m+2/m^-m通分:(1)x/6ab^2,y/9a^2bc(2)1/m-n,2/n^2-m^2,3n/2(m+n)求解答,
约分:
(1)x^2+6x+9/x^2-9
(2)m^-3m+2/m^-m
通分:
(1)x/6ab^2,y/9a^2bc
(2)1/m-n,2/n^2-m^2,3n/2(m+n)求解答,

约分:(1)x^2+6x+9/x^2-9(2)m^-3m+2/m^-m通分:(1)x/6ab^2,y/9a^2bc(2)1/m-n,2/n^2-m^2,3n/2(m+n)求解答,
(1)x^2+6x+9/x^2-9
=(x+3/x)^2-9
=(x+3/x+3)(x+3/x-3)
(2)m^2-3m+2/m^-m
=m^2-4m+2/m^2
通分:
(1)x/6ab^2,y/9a^2bc
3xac/18a^2b^2c,2yb/18a^2b^2c
(2)1/m-n,2/n^2-m^2,3n/2(m+n)
2(n+m)/2(n+m)(n-m),4/2(n+m)(n-m),3n(n-m)/2(n+m)(n-m)

第一问,原式=(x+3)²/(x+3)(x-3)=(x+3)/(x-3)
第二问,原式=(m-1)(m-2)/m(m-1)=m-2/m
通分的式子 没看懂 你写分开点

1 原试=(x+3)^2/(x-3)(x+3)=x+3/(x-3)
2 (m-2)(m-1)/m(m-1)=m-2/m
1 3acx/18a^2b^2c 2by/18a^2b^2c
2 2(m+n)/2(m^2-n^2) 4/2(m^2-n^2) 3n(m-n)/2(m^2-n^2)

(1) (x+3)^2/((x+3)(x-3))=(x+3)/(x-3)
(2) (m-1)(m-2)/(m(m-1))=(m-2)/m
(1) x/6ab^2=3acx/18a^2b^2c,y/9a^2bc=2by/18a^2b^2c
(2) 1/m-n,2/n^2-m^2,3n/2(m+n) 公分母是2(m+n)(m-n),分子分别是2(m+n),-4,3n(m-n)