lim(1/1*4+1/4*7+1/7*10..+1/(3n-2)(3n+1)=

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lim(1/1*4+1/4*7+1/7*10..+1/(3n-2)(3n+1)=

lim(1/1*4+1/4*7+1/7*10..+1/(3n-2)(3n+1)=
lim(1/1*4+1/4*7+1/7*10..+1/(3n-2)(3n+1)=

lim(1/1*4+1/4*7+1/7*10..+1/(3n-2)(3n+1)=
lim(1/1*4+1/4*7+1/7*10..+1/(3n-2)(3n+1)
=lim[1/3(1-1/4)+1/3(1/4-1/7)+.+1/3(1/3n-2-1/3n+1)]
=lim[1/3(1-1/(3n+1))]
=lim[n/(3n+1)]
=lim[1/(3+1/n)]
=1/3
n-->+∞

lim[(4+7+...+3n+1)/(n^2-n)]= lim(7-1/n)=?是不是可以把7和1/n单独分开看,就是lim(an)=7,lim(bn)=lim(1/n)=0,lim(an-bn) =lim(7-1/n)=7,或者lim(bn)=lim(-1/n)=0,那么lim(an+bn)=lim(7+(-1/n))=lim(7-1/n)=7所以lim(7-1/n) lim(2an+4bn)=1 lim(3an-bn)=2 求lim(an+bn) lim(2an+4bn)=1 lim(3an-bn)=2 求lim(an+bn) lim[x-1%x+1]^[+4] {An}{Bn},若lim(3An+Bn)=8,lim(6An-Bn)=1求lim(4An-Bn)与lim(AnBn)的值 计算下列极限:1)lim(n→∞) 1/n3 2)lim(n→∞)4n+1/3n-11)lim(n→∞) 1/n3 2)lim(n→∞)4n+1/3n-13) lim(n→∞) (1/3)n4)lim(n→∞)n3+2n-5/5n3-n 5) lim(n→∞)(1+1/2n)n 6) lim(n→∞)2x3-x2+1/3x2+2x-9 7) lim(x→0 )sin3x/sin7x8) lim 2x³+3x²+5/7x³+4x²-1 的极限 ,lim e x5-1/x(e,x的五次方) lim(2x^3-3x^2+1)/[(x-1)(4x^n+7)] 则n=lim趋向于无穷大 1.lim (1-7x)^(4/x) (x趋近0)2.lim (4x-3)/ln(3+5e^x) (x趋近正无穷) 数学难题,求指教~~极限到底是什么玩意我还不懂.1.lim(x^2-2x+6)2.lim(x^2-4)/(x-2)3.lim(x^2-6x=8)/(x^-5x=4)4.lim[1/(1-x)-1/(1-x^3)5.lim(sin2x)/x^26.lim(sin5x)/x7.lim(tan3x)/(sin7x)8.lim[(1+x)/x]^2x例如这道例题~lim[(1/3)x+1] lim(1+4+7+…+(3n-2))/(7n^2-5n), lim 1+4+7+...+(3n-2)/n(n+1)=______ lim(1/n^2+4/n^2+7/n^2+…+3n-1/n^2) 一道数学题lim f(X)=3 (X---1-)and lim f(x)=7 (x---1+)问lim x----1 f(x)是否存在? lim(2x^3+3x^2+5)/(7x^3+4x^2-1) lim[(x^5+7x^4+2)^1/5-x]=b,求,b的值. lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-2)/(x+1)]*2x} = -4