1/(x+1)+1/(x+5)=1/(x+2)+1/(x+4) 这题怎么做?

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 06:52:16
1/(x+1)+1/(x+5)=1/(x+2)+1/(x+4) 这题怎么做?

1/(x+1)+1/(x+5)=1/(x+2)+1/(x+4) 这题怎么做?
1/(x+1)+1/(x+5)=1/(x+2)+1/(x+4) 这题怎么做?

1/(x+1)+1/(x+5)=1/(x+2)+1/(x+4) 这题怎么做?
1/ (x+1) + 1/(x+5) = 1/(x+2) + 1/(x+4)==> 1/ (x+1) - 1/(x+2)= 1/(x+4) - 1/(x+5)
==> 1/[(x+1)(x+2)] = 1/[(x+4)(x+5)]
==> (x+1)(x+2) = (x+4)(x+5)
==> x^2 + 3x + 2 = x^2 + 9x + 20
==> 6x = -18
==> x = -3

x*x*x*x+2008x*x+2007x+2008(提示:x*x*x-1=(x-1)*(x*x+x+1)) 3/x-1=4/x 6/x+1=x+5/x(x+1) 若1+x+x*x+x*x*x=0,求x+x*x+x*x*x+.+x(2000次幂) 解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1 请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360 f(x)=x*x-5x+1/x*x*x,求导x的三次方分之x的平方减去5x加上1 已知x除以(x*x-x+1)=7,求x*x除以(x*x*x*x+x*x+1)的值 解下列方程!就三道!解下列方程.1、x/x-2 - 1-x²/x²-5x = 2x/x-3(x/x-2 - 1-x²不是一起的!)2、5x/x²+x-6 - 5-2x/x²-x-12=7x-10/x²-6x+8(5x/x²+x-6 - 5-2x不是一起的!)3、x-4/x-5 + x-8/x-9=x-7/x- 1.(1/X-1 )-2=X^-3X/X^-12.(X/X+1)^+5(X/X+1)+6=03.(8(X^+2X)/X^-1)+ 3(X^-1)/X^+2x x+5/x+1-3x-3/x+5=8x+28/x^2+4X-5-2(x+5)/(x+1)-(3x-3)/(x+5)=(8x+28)/(x^2+4X-5)-2 x/(x-2)-(1-x ² )/(x ² -5x+6)=(2-x)/(x-3) 解方程,急 *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || [x(x+1)+x平方(x-1)]+(-3x) 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 求:(x-2)(x²-6x-9)-x(x-3)(x-5)其中x=三分之一.以及x²(x-1)-x(x²+x-1)其中x=二分之一的答案 x(x^2-1)+2x^2 *(x+1)-3x*(2x-5)=x(3x^2-4x)-28 计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1 麻烦解4道分式方程(20分)(x/2x-5)+(5/5-2x)=1(x+1/x*x-2x)-(1/x)=3/x-2(1-x/5-x)-(5-x/1-x)=8/x*x-6x+5(x+1/x-1)-(4/x*x-1)=1去掉括号,不管前面正负,都不变号~