作业帮已知某二元酸H2A,其电离方程式为：H2A==H++HA-,HA-==H++A2-,测得25℃时,0.1 mol/L的H2A溶液中[H+]=0.11mol/L,则该条件下,HA-的电离度是 CA.11% B.9.1% C.10% D.20%
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/04 06:10:23
![已知某二元酸H2A,其电离方程式为：H2A==H++HA-,HA-==H++A2-,测得25℃时,0.1 mol/L的H2A溶液中[H+]=0.11mol/L,则该条件下,HA-的电离度是 CA.11% B.9.1% C.10% D.20%](/uploads/image/z/1242860-68-0.jpg?t=%E5%B7%B2%E7%9F%A5%E6%9F%90%E4%BA%8C%E5%85%83%E9%85%B8H2A%2C%E5%85%B6%E7%94%B5%E7%A6%BB%E6%96%B9%E7%A8%8B%E5%BC%8F%E4%B8%BA%EF%BC%9AH2A%3D%3DH%2B%2BHA-%2CHA-%3D%3DH%2B%2BA2-%2C%E6%B5%8B%E5%BE%9725%E2%84%83%E6%97%B6%2C0.1+mol%2FL%E7%9A%84H2A%E6%BA%B6%E6%B6%B2%E4%B8%AD%5BH%2B%5D%3D0.11mol%2FL%2C%E5%88%99%E8%AF%A5%E6%9D%A1%E4%BB%B6%E4%B8%8B%2CHA-%E7%9A%84%E7%94%B5%E7%A6%BB%E5%BA%A6%E6%98%AF+CA.11%25+B.9.1%25+C.10%25+D.20%25)
已知某二元酸H2A,其电离方程式为：H2A==H++HA-,HA-==H++A2-,测得25℃时,0.1 mol/L的H2A溶液中[H+]=0.11mol/L,则该条件下,HA-的电离度是 CA.11% B.9.1% C.10% D.20%
已知某二元酸H2A,其电离方程式为：H2A==H++HA-,HA-==H++A2-,测得25℃时,0.1 mol/L的H2A溶液中[H+]=0.11mol/L,则该条件下,HA-的电离度是 C
A.11% B.9.1% C.10% D.20%
已知某二元酸H2A,其电离方程式为：H2A==H++HA-,HA-==H++A2-,测得25℃时,0.1 mol/L的H2A溶液中[H+]=0.11mol/L,则该条件下,HA-的电离度是 CA.11% B.9.1% C.10% D.20%
首先0.1 mol/L的H2A完全电离成0.1 mol/L的HA-和0.1 mol/L的H+
而溶液中[H+]=0.11mol/L
所以0.1 mol/L的HA-电离出0.01mol/L的H+,显然有0.01mol/L的HA-发生电离
所以HA-的电离度=0.01/0.1=10%
选C(电离度是指已电离的占总的比例)