(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^16

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(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^16

(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^16
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^16

(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^16
原式=(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)/(1-1/2)+1/2^16
=2(1-1/2^16)+1/2^16 前面每两项结合为平方差公式
=2-1/2^16

1 2 1 2 () () ()() 1+1/2^2 1 1 1 1 1 1 1 1 1 1 1 -+-2 2 1+2+1+2+1+2+1+2+1+2+1+2+1+2 =( )*( ) =() (1-1/2^2)(1-1/3^2)(1-1/4^2).(1-1/2009^2), （1+1/2+1/3+... 计算行列式 2 1 1 1 ,1 2 1 1 ,1 1 2 1,1 1 1 2, 1/2-1/(n+1) 证明 1+1/1+1/1*2+1/1*2*3+.+1/1*2*3*...*n [(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)] (1-1/2^2)*(1-1/3^2)*(1-1/4^2)*.*(1-1/2002^2)*(1-1/2003^2) (1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16), 1*1/2=? 1+1+2+56 5,2,1,1, 1/2+56/1 1.1/2. 2x-1-1