(1)(√3)/(2)-(1)/(√3-1)+﹙-√2﹚^0+﹙2-√3﹚^-1;(2)﹙√3+1﹚﹙√3-1﹚+﹙√3-1﹚^0-﹙-﹙1/3﹚﹚^-2;(3)﹙1/3﹚^-1+16÷﹙-2﹚^3+﹙2006-(π/5)﹚^0-3;(4)﹙1/3

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 08:24:03
(1)(√3)/(2)-(1)/(√3-1)+﹙-√2﹚^0+﹙2-√3﹚^-1;(2)﹙√3+1﹚﹙√3-1﹚+﹙√3-1﹚^0-﹙-﹙1/3﹚﹚^-2;(3)﹙1/3﹚^-1+16÷﹙-2﹚^3+﹙2006-(π/5)﹚^0-3;(4)﹙1/3

(1)(√3)/(2)-(1)/(√3-1)+﹙-√2﹚^0+﹙2-√3﹚^-1;(2)﹙√3+1﹚﹙√3-1﹚+﹙√3-1﹚^0-﹙-﹙1/3﹚﹚^-2;(3)﹙1/3﹚^-1+16÷﹙-2﹚^3+﹙2006-(π/5)﹚^0-3;(4)﹙1/3
(1)(√3)/(2)-(1)/(√3-1)+﹙-√2﹚^0+﹙2-√3﹚^-1;
(2)﹙√3+1﹚﹙√3-1﹚+﹙√3-1﹚^0-﹙-﹙1/3﹚﹚^-2;
(3)﹙1/3﹚^-1+16÷﹙-2﹚^3+﹙2006-(π/5)﹚^0-3;
(4)﹙1/3﹚^-1-│-√2│+﹙5-π﹚^0+﹙1﹚/﹙√2-1﹚.

(1)(√3)/(2)-(1)/(√3-1)+﹙-√2﹚^0+﹙2-√3﹚^-1;(2)﹙√3+1﹚﹙√3-1﹚+﹙√3-1﹚^0-﹙-﹙1/3﹚﹚^-2;(3)﹙1/3﹚^-1+16÷﹙-2﹚^3+﹙2006-(π/5)﹚^0-3;(4)﹙1/3
(1)√3/2-(√3+1)/2+1+1/(2-√3)=1/2+2+√3=5/2+√3
(2)3-1+1-1/(1/3)^2=3-9=-6
(3)1/(1/3)+16/(-8)+1-3=3-2+1-3=-1
(4)1/(1/3)-√2+1+√2+1=3-√2+1+√2+1=5

1.=(√3)/(2)-(1)/(√3-1)+﹙2-√3﹚^-1
=(√3)/(2) - (√3+1)/(2) + (1)/(2-√3)+1
=(√3)/(2) - (√3+1)/(2) + (2+√3)/(1)+1
=-1/2 +2+√3+1
=5/2+√3
2.=3-1+1-9
=-6
3.=3-2+1-3...

全部展开

1.=(√3)/(2)-(1)/(√3-1)+﹙2-√3﹚^-1
=(√3)/(2) - (√3+1)/(2) + (1)/(2-√3)+1
=(√3)/(2) - (√3+1)/(2) + (2+√3)/(1)+1
=-1/2 +2+√3+1
=5/2+√3
2.=3-1+1-9
=-6
3.=3-2+1-3=-1
4.=3-√2+1+√2+1
=5
祝学习进步@@

收起

(1)(√3)/(2)-(1)/(√3-1)+﹙-√2﹚^0+﹙2-√3﹚^-1;
=√3/2-(√3+1)/2+1+2+√3
=-1/2+3+√3
=5/2+√3
(2)﹙√3+1﹚﹙√3-1﹚+﹙√3-1﹚^0-﹙-﹙1/3﹚﹚^-2;
=2+1-9
=-6
(3)﹙1/3﹚^-1+16÷﹙-2﹚^3+﹙2006-(π/5)﹚^0-3;<...

全部展开

(1)(√3)/(2)-(1)/(√3-1)+﹙-√2﹚^0+﹙2-√3﹚^-1;
=√3/2-(√3+1)/2+1+2+√3
=-1/2+3+√3
=5/2+√3
(2)﹙√3+1﹚﹙√3-1﹚+﹙√3-1﹚^0-﹙-﹙1/3﹚﹚^-2;
=2+1-9
=-6
(3)﹙1/3﹚^-1+16÷﹙-2﹚^3+﹙2006-(π/5)﹚^0-3;
=3-16÷8+1-3
=-1
(4)﹙1/3﹚^-1-│-√2│+﹙5-π﹚^0+﹙1﹚/﹙√2-1﹚
=3-√2+1+√2+1
=5.

收起