x^2cosθ-x(1-x)+(1-x)^2sinθ

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x^2cosθ-x(1-x)+(1-x)^2sinθ
cos x>-1/2

cosx>-1/2cosx>-1/2cosx>-1/2画出y=cosx在[-π,π]的图像,由于cos(-2π/3)=cos(2π/3)=-1/2于是在[-π,π]内,由cosx>-1/2得-2π/3

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